Pictorial & Optimization Puzzles (Week 7)
There are two puzzles below. One of them is "pictorial puzzle" and the other
one is "optimization puzzle". You can answer only one of them. You can
answer the pictorial puzzle only once in first 7 days and you can answer the
optimization puzzle three times in 14 days. Maximum 350 points can be earned
from the optimization puzzle and Maximum 165 points can be earned from the
pictorial puzzle. Be sure that you are using the answer form of the puzzle
type you selected. Before submitting your answer, you should carefully read
the instructions on the answer format, and you should submit your answer
accordingly. If not, you may face undesirable consequences, such as the
ruling out of a correct answer. Especially, for the optimization puzzle; to
submit an answer fitting the rules and to do the other important procedures
(For instance, sending the solution file with e-mail after entering each of
your answer(s) within 24 hours etc.), analyze the text of the puzzle
carefully and read again The Competition Rules!

Pictorial Puzzle

HINT:

Optimization Puzzle

Use the eight objects above as much as the numbers which are top of them, at
most. By uniting them, form the numbers below (with same shape) and perform
a mathematical operation with these numbers.

You can rotate or reverse (mirror view) the objects when you form the
numbers.
You have to use all the mathematical signs (+, -, /, x, =) only once at your
mathematical operation.
The numbers you used must be integer at the operation and the result.
ATTENTION!
Also the numbers at the result of the operation must be formed by the
objects. (Look at the example)
Calculate the result in oder left to right. (like a calculator)
The calculation at the example: 1 + 7 - 2 / 6 x 26 = 26
1+7=8, 8-2=6, 6/6=1, 1x26=26
To increase your score, you must increase the result of your operation.
SCORE CALCULATION:
If there is/are not object(s) at the end of the calculation, multiply the
result of the calculation by 3. This will be your score.
If the object(s) remain(s);
Count the total cells of the remaining objects.
Then divide the result of the operation by this total cell count. Then add
it to result of the operation.
If the result of this division is not integer, round the result to the
nearest integer. (Examples: 26,49 = 26  and  26,50 = 27)
You cannot use the objects more times than the numbers above them.
  EXAMPLE SOLUTION:

Remaining Objects:

  The result of the operation: 26
  The total cell count of the remainig ojects: 26
  Score: 26/26+26 = 27

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